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4 votes
4 votes
14

What would be the slope of equation #1 in the following system? (Graphing)
2x+3y=12
4x-3y=15
(Worth 10 points )
A:1/2
B: -1
C:3/4
D:-2/3

User Milan Gupta
by
2.9k points

1 Answer

26 votes
26 votes

Answer:


m = -(2)/(3)

Explanation:

Given


2x+3y=12


4x-3y=15

Required

Slope of #1


2x+3y=12

Make y the subject


3y = -2x + 12

Divide through by 3


y = -(2)/(3)x + (12)/(3)


y = -(2)/(3)x + 4

An equation has the form:


y = mx + c

Where


m = slope

Compare
y = mx + c and
y = -(2)/(3)x + 4


m = -(2)/(3)

Hence, the slope is
-(2)/(3)

User David Tuite
by
2.8k points