Question

D) find the power cunsumption in 22 ohms lamp and 4.5 ohms lamp ?

e) find the power delivered by the battery

Answer 1

Step-by-step explanation:

R₁ = 22 Ω

R₂ = 4.5 Ω

U = 45 V

Circuit resistance:

R = R₁ + R₂ = 22 + 4.5 = 26.5 Ω

Circuit current:

I = I₁ = I₂ = U / R = 45 / 26.5 ≈ 1.7 А

Lamp voltages:

U₁ = I₁·R₁ = 1.7·22 ≈ 37 V

U₂ = I₂·R₂ = 1.7·4.5 ≈ 8 V

Power:

P₁ = U₁·I₁ = 37·1.7 ≈ 63 W

P₂ = U₂·I₂ = 8·1.7 ≈ 14 W

P = U·I = 45·1.7 ≈ 77 W