Question

An athlete is running a circular track of radius 50m after he completed 2 revolution, what will be.

A, displacement B, distance​

Answer 1

displacement=√50^2+50^2=70.71m

Step-by-step explanation:

Distance traveled by the athlete=length of the arc

=d(theta)r

Here the athlete runs 3\4of a circle whose radius is 50 m

here, d(theta)=3(pi)/2rad

hence distance=3(pi)/2 x 50

=235.61 m

displacement=the chord between the initial point and the final point. it subtends an angle of 90degrees at the centre of the circle.

it forms a right angled triangle.

hence by Pythagoras theorem,

displacement=√50^2+50^2=70.71m