Question

P is the point (0,-1) and Q is the point (5,9) find the equation of the line through P that is perpendicular to PQ

Answer 1

Explanation:

Find the slope of PQ

`(9 - (-1))/(5-0)=(10)/(5)` or just
`2`

The perpendicular slope is the negative reciprocal

Use a slope of
`-(1)/(2)`

Use the point-slope form of a equation and point P to find a new equation in slope-intercept form

`(y- (-1))=-(1)/(2)(x-0)`

`y+1=-(1)/(2) x`

Subtract the 1 from both sides of the equation

`y=-(1)/(2)x-1`