Question

2KCIO3 -> 2KCI+ 302

How many moles of oxygen are produced by
the decomposition of 6.0 moles of potassium
chlorate, KCIO3?

Answer 1

9 moles

Step-by-step explanation:

The balanced chemical equation for this decomposition reaction is as follows:

2KCIO3 → 2KCI+ 302

Based on this equation, 2 moles of potassium chlorate (KCIO3) decomposes to form 3 moles of oxygen gas (O2).

Hence, 6 moles of pottasium chlorate will decompose to produce;

6 × 3 ÷ 2

= 18 ÷ 2

= 9 moles of O2.