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Write an equation of a line that is

parallel to y = 1/3x + 5 and goes
through (3,5)
A) y = -3x + 14
B) y = 1/3x + 4
C) y = 1/3x + 4/3
D) y = 3x + 1
E) y = 1/2x + 7/2

User Nohup
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1 Answer

3 votes

Answer:

Explanation:

We'll look for an equation in the format y = mx + b where m is the slope and b the y-intercept. A characteristic of parallel lines is that they have the same slope. That means the same value of m for both equations.

The reference equation is y = 1/3x + 5, It has a slope of (1/3). This means the new line will also have a slope of (1/3), and so we can write:

y = (1/3)x + b

Any value of b will result in a parallel line to y = 1/3x + 5. But the new line comes with the requirement that it go through point (3,5). That's easily done if we choose the correct value for b, the y-intercept. We could graph the line to visually determine what value of b will make the line go through this point, or we can simply enter the given point in the above equation and solve for b:

y = (1/3)x + b (for point (3,5)

5 = (1/3)(3) + b

5 = 1 + b

b = 4

A b value of four will shift the line so that it intersects (3,5). See the attached graph.

Write an equation of a line that is parallel to y = 1/3x + 5 and goes through (3,5) A-example-1
User BigCheesy
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