Ax^2 +Bx + C
x^2 +11x +24
Using the number in place of C gives us what values could be inside the brackets.
For 24 the multiples are
1 and 24
2 and 12
3 and 8
4 and 6
We want the one that can add or subtract to give the number in place of B, which is 11.
The only multiples that add to 11 are 3 and 8
Therefore we know that 8 and 3 need to be in the brackets.
Giving us (x+8)(x+3)