Question

The hypotenuse of a right triangle measures 10 cm and one of its legs measures 8 cm.

Find the measure of the other leg. If necessary, round to the nearest tenth.

Answer 1

`\textit{using the pythagorean theorem} \\\\ c^2=a^2+b^2\implies √(c^2 - a^2)=b \qquad \begin{cases} c=\stackrel{hypotenuse}{10}\\ a=\stackrel{adjacent}{8}\\ b=opposite\\ \end{cases} \\\\\\ √(10^2-8^2)=b\implies √(36)=b\implies 6=b`