Identify a quadratic function in standard form with zeros 5 and -1
x (2) + (2)x - 15 = 0
X=3 and x= -5
(x - 3) = 0 and (x + 5) = 0
Explanation:
Using Vieta's formula
x²-(sum of roots)x+(product of roots)=0
x²-(5+-1)x+(5×-1)=0
x²-4x-5=0
Alternatively,
if the zeros are 5 and -1 then the quadratic factorizes to (x-5)(x+1) Now expand it
x²+x-5x-5=0
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