Question

Write an equation in standard form of the line that passes through (-8,0) and has the slope m= -4.

Answer 1

standard form for a linear equation means

• all coefficients must be integers, no fractions

• only the constant on the right-hand-side

• all variables on the left-hand-side, sorted

• "x" must not have a negative coefficient

`(\stackrel{x_1}{-8}~,~\stackrel{y_1}{0})\hspace{10em} \stackrel{slope}{m} ~=~ - 4 \\\\\\ \begin{array}c \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{0}=\stackrel{m}{- 4}(x-\stackrel{x_1}{(-8)}) \implies y -0= -4 (x +8) \\\\\\ y=-4x-32\implies {\Large \begin{array}{llll} 4x+y=-32 \end{array}}`