Question

Find three consecutive numbers whose sum is 1020

Answer 1

Answer: 339 + 340 + 341 = 1020

Explanation:

3X + 3 = 1020
3X + 3 - 3 = 1020 - 3
3X = 1017
3X/3 = 1017/3
X = 339

Which means that the first number is 339, the second number is 339 + 1 and the third number is 339 + 2. Therefore, three consecutive integers that add up to 1020 are 339, 340, and 341.

339 + 340 + 341 = 1020

_Hope that helped_

Answer 2

what's up? the answer to this is 339+340+341

best of luck with your studies