Question

Write the equation of the circle in standard form that has the following: Center (-5,7) and Radius = 4

Answer 1

`(x+5)^(2)+(y-7)^(2) =16`

Explanation:

The Standard Form of Circle Equation whose Center is at ( h , k) and Radius of r is given by

`(x-h)^(2)+(y-k)^(2) =r^(2)`

So for our Question

we have ( h , k ) = ( -5 , 7 ) and r = 4

By substitution

`(x-(-5))^(2)+(y-7)^(2) =4^(2)`

Simplify
`(x+5)^(2)+(y-7)^(2) =16`