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3x+y-4z=-22
2x+3y+4z=32
x-y+2z=16

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1 Answer

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Answer: x=-1, y=2, z=-3

Explanation:

[1] 2x + 3y - 4z = 16

[2] -x + 2y - z = 8

[3] 2x - y - 2z = 2

Solve by Substitution :

Solve equation [3] for the variable y

[3] y = 2x - 2z - 2

Plug this in for variable y in equation [1]

2x + 3•(2x-2z-2) - 4z = 16

8x - 10z = 22

Plug this in for variable y in equation [2]

-x + 2•(2x-2z-2) - z = 8

3x - 5z = 12

Solve equation [2] for the variable x

3x = 5z + 12

x = 5z/3 + 4

Plug this in for variable x in equation [1]

8•(5z/3+4) - 10z = 22

10z/3 = -10

10z = -30

Solve equation for the variable z

10z = - 30

z = - 3

By now we know this much :

x = 5z/3+4

y = 2x-2z-2

z = -3

Use the z value to solve for x

x = (5/3)(-3)+4 = -1

Use the x and z values to solve for y

y = 2(-1)-2(-3)-2 = 2

User Yossarian
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