183k views
20 votes
A ball is dropped from a cliff that is 135 m high.

The relationship between the height of the ball,
h, in metres, and time, t, in seconds, can be
represented by the equation h = –4.9t
2 + 135.
Which is closest to the height of the ball after
2.1 seconds?

1 Answer

11 votes

Answer:

113 feet

Explanation:

I will assume you meant h = -4.9t^2 + 135; "t2" is incorrect.

To answer this question, to find the height of the ball after 2.1 seconds, substitute 2.1 for t in the above equation:

h(2.1) = -4.9(2.1)^2 + 135. This becomes -21.6 + 135, or 113.4.

The closest result to the height of the ball after 2.1 seconds is 113 feet.

User Tomi Lammi
by
7.6k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories