Answer:
Can't be solved
Explanation:
Using Pythagoras theorem,
H2= O2 + A2 (where, H= Hypotenuse,O=Opposite,A=Adjacent)
The hypotenuse,H=7feet long
If the opposite side of the triangle is 4 feet longer than the adjacent side, then;
O=A+4
while, A=A
,then using H^2= O^2 + A^2(The 2 are power,that is square)
7^2 = (A+4)^2 + A^2
49= (A+4)(A+4) + A^2
49=A^2 +4A+4A+16 + A^2
49=A^2+8A+16+A^2
(collect like terms)
49-16=A^2+A^2+8A
33=2A^2+8A
Then a quadratic equation,
2A^2+8A=33
2A^2+8A-33=0,
using (-b+/-√4ac) /2a
where b=8, a=2, c=-33
[-8 +/-√4*2*(-33) ]/2(2)
-8 +/-