Question

Help meeeeeeeeeee pleaseeeeeeeeeeeee!!!!!!!!!!!!!!!!!!!!!!!!

Answer 1

The object has fallen
`\boxed{\sf 289}` feet from ts intial position.

Step-by-step Step-by-step explanation:

Given:

Formula:

`\rm v = √(2gh)`

Where,

v = velocity (in feet per second)

h = Height fallen (in feet)

g = acceleration due gravity (in feet per second squared) = approximately 32 ft/s²

To find:

How far an object has fallen if its velocity (v) is 136 ft/s

Solution:

By substituting the value of g & v in the formula we get:

`\rm \implies 136 = √(2 * 32 * h) \\ \\ \rm \implies 136 = √(64h) \\ \\ \rm \implies 64h = {136}^(2) \\ \\ \rm \implies h = \frac{ {136}^(2) }{64} \\ \\ \rm \implies h = (18496)/(64) \\ \\ \rm \implies h = 289 \: ft`