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A 1.5 kg ball is dropped so that is is traveling at a velocity of -27 m/s when it hits the ground. If the ball rebounds upward with the same speed, what is the change in momentum of the ball?
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A 1.5 kg ball is dropped so that is is traveling at a velocity of -27 m/s when it hits the ground. If the ball rebounds upward with the same speed, what is the change in momentum of the ball?

User Chris Tapay
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1 Answer

1 vote

Answer:

The change in momentum of the ball = 81 kg·m/s

Step-by-step explanation:

Given:

m = 1.5 kg

V₁ = - 27 m/s

V₂ = + 27 m/s

____________

Δp - ?

The change in momentum of the ball:

Δp = m·ΔV

Δp = m· (V₂ - V₁) = 1.5·(27 - (-27)) = 1.5·(27 + 27) = 81 kg·m/s

User Ashkan Rahmani
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