Question

Moving a charge from point A

A
, where the potential is 350 V
V
, to point B
B
, where the potential is 130 V
V
, takes 4.7×10−4 J
J
of work.

Answer 1

Step-by-step explanation:

Given:

φ₁ = 350 V - potential of point A

φ₂ = 130 V - potential of point B

A = 4.7·10⁻⁴ J - Work of the electric field

______________________

Q - ?

The magnitude of the electric charge:

Q = J / Δφ

Potential difference:

Δφ = φ₁ - φ₂ = 350 - 130 = 120 V

Then:

Q = J / Δφ = 4.7·10⁻⁴ / 120 ≈ 3.9·10⁻⁶ C or Q

Q = 3.9 mkC