Question

What is an equation of the line that passes through the points (-4, -3) and (8, 6)?

Answer 1

Answer:
`y=(3)/(4) x`

Explanation:

We will create a point-slope equation to solve.

First, we need to find the slope.

`\displaystyle (y_2-y_1)/(x_2-x_1)= (6--3)/(8--4) =(9)/(12) =(3)/(4)`

Next, we will create our point-slope equation.

`\displaystyle y-y_1=m(x-x_1)`

`\displaystyle y--3=(3)/(4) (x--4)`

`\displaystyle y+3=(3)/(4) (x+4)`

`\displaystyle y=(3)/(4) x+3 -3`

`\displaystyle y=(3)/(4) x`