Question

Please show your work!***

Remember, M (molarity) = moles of solute / liters of solution
1) What is the molarity of an aqueous solution containing 40g of C6H12O6 in a 1.5L of solution?
2) Calculate the molarity of a 1.60L of a solution containing 1.55g of dissolved KBr.
3) What is the molarity of an bleach solution containing 9.5g of NaOCl per 1L of bleach?

Answer 1

1. 0.48 M 2. 0.00814 M 3. 0.1276 M

Step-by-step explanation:

1. Convert the 40 g to moles using the molar mass of C6H12O6:

40 g C6H12O6/180.16 g C6H12O6 = 0.222 mol

Then divide the number of moles by liters to find molarity:

0.222 mol/1.5 L = 1.48 M

2. Convert the 1.55 g to moles using the molar mass of KBr:

1.55 g KBr/119 g KBr = 0.013025 mol

Then divide the number of moles by liters to find molarity:

0.013025 mol/1.60 L = 0.00814 M

3. Convert the 9.5 g to moles using the molar mass of NaOCl:

9.5 g NaOCl/180.16 g NaOCl = 0.1276 mol

Then you divide the number of moles by liters to find molarity:

0.1276 mol/1 L = 0.1276 M