Question

Human blood types are determined by genes that follow the codominance pattern of inheritance. there are two dominant alleles (a and b) and one recessive allele (o). if a man that has the blood type aa mates with a woman that has the blood type bo. what are the chances of them having a baby that has "a" blood type?

Answer 1

50%

Step-by-step explanation:

Blood type a and b are codominant, so lets express as 'A and B'

Blood type o is recessive, so is expressed as little 'o'

A man has blood type aa which needs to be written as dominant (in caps) = AA

A woman has blood type bo. The b needs to be dominant and the o stays as little 'o' = Bo

As you can see in the punnet square I have drawn the alleles of the man (AA) at the top and the alleles of the woman (Bo) on the left side to find the alleles of the offspring.

We have the alleles:

AB, AB, Ao, Ao

AB = blood type AB because A and B are codominant which are expressed equally

Ao = blood type A as only A is dominant here which takes express over the recessive 'o'

We have 2 'Ao' out of 4

2/4 = 0.5

0.5 × 100 = 50%