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A 487 kg bear grasping a vertical tree slides down at constant velocity. The acceleration of gravity is 10 m/s². What is the friction force that acts on the bear? Answer in units of N.
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A 487 kg bear grasping a vertical tree slides

down at constant velocity.
The acceleration of gravity is 10 m/s².
What is the friction force that acts on the
bear?
Answer in units of N.

User Okan Aslankan
by
5.2k points

1 Answer

4 votes

Answer:

4870 N

Step-by-step explanation:

Since he is not accelerating

the force is equal to his weight mg = 487 * 10 = 4870 N

User Bisca
by
4.8k points
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