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Help please?
I don't understand.

Help please? I don't understand.-example-1

1 Answer

5 votes

Given Equation:-


\boxed{ \tt (3)/(x + 5) - (2)/(x - 3)}

Step by step expansion:


\dashrightarrow\sf(3)/(x + 5) - (2)/(x - 3)

Write the equation


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\dashrightarrow\sf((3 * (x + 5)(x - 3))/(x + 5) - (2 * (x + 5)(x - 3))/(x - 3))/((x + 5)(x - 3))

Take the lcm of the equation I.e (x + 5) (x + 3)


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\dashrightarrow\sf\frac{\frac{3 * \cancel{(x + 5)}(x - 3)}{\cancel{x + 5}} - \frac{2 * (x + 5)\cancel{(x - 3)}}{\cancel{x - 3}}}{(x + 5)(x - 3)}

cancel like terms I.e (x + 5) with (x+ 5) and (x - 3) with (x - 3)


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\dashrightarrow\sf((3 * (x - 3))/(1) - (2 * (x + 5))/(1))/((x + 5)(x - 3))


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\dashrightarrow\sf(3 * (x - 3)- 2 * (x + 5))/((x + 5)(x - 3))

Remove 1 as denominator


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\dashrightarrow\sf(3x - 9- 2 (x + 5))/((x + 5)(x - 3))

Multiply 3 with x - 9


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\dashrightarrow\sf(3x - 9- 2 x - 10)/((x + 5)(x - 3))

Multiply - 2 with x + 5


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\dashrightarrow\sf(3x - 2x- 9 - 10)/((x + 5)(x - 3))

Arrange the equation so that it would be easier to solve.


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\dashrightarrow\sf(x- 9 - 10)/((x + 5)(x - 3))

Subtract 3x with 2x


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\dashrightarrow\bf(x-19)/((x + 5)(x - 3))

Add -9 with - 10


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\therefore \underline {\textsf{\textbf{Option \red{one} is correct}}}

User FWDekker
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