What is the value of z where distance of between two point R(6, - 1, - 3) and S(3, 3, z) is 13?

asked Apr 2, 2023 225k views

4 votes

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4 votes

Answer:

-15, 9

Explanation:

Substituting into the distance formula,

$√((6-3)^2+(-1-3)^2+(-3-z)^2)=13 \\ \\ √(25+(3+z)^2)=13 \\ \\ 25+(3+z)^2=169 \\ \\ (3+z)^2=144 \\ \\ 3+z=\pm 12 \\ \\ z=-3 \pm 12 \\ \\ z=-15, 9$

Kim Major answered Apr 6, 2023

5.3k points

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