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What is the solution of the linear-quadratic system of equations y=x^2+2x-3 y=2x+1

What is the solution of the linear-quadratic system of equations y=x^2+2x-3 y=2x+1-example-1
User Double AA
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1 Answer

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Answer:

(x, y) = {(-2, -3), (2, 5)}

Explanation:

You want to solve the system of equations y=x²+2x-3 and y=2x+1.

Solution

The two expressions for y can be equated, and the resulting equation put in standard form.

x² +2x -3 = 2x +1

x² -4 = 0 . . . . . . . . . . subtract (2x+1)

(x -2)(x +2) = 0 . . . . . factor

Values of x that make the factors zero are 2 and -2.

Corresponding values of y are ...

y = 2x +1 = 2(2) +1 = 5

y = 2(-2) +1 = -3

Solutions are ...

  • (x, y) = (2, 5)
  • (x, y) = (-2, -3)
What is the solution of the linear-quadratic system of equations y=x^2+2x-3 y=2x+1-example-1
User Harjit Singh
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8.2k points

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