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Find two numbers that have the given product and the given sum 36,16

User ResponsiblyUnranked
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1 Answer

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13 votes

Answer:

It differs by 4

16 - 12 = 4

4 = 4

Their product is 192

(16) (12) = 192

192 = 192

Step-by-step explanation: The sum of two numbers is 60 and their product is 576. Find the numbers. Let x and y are the two consecutive integers

The sum of two numbers is 60

x + y = 60 ---- (1)

Product of two numbers = 576

xy = 576

y = 576/x ----- (2)

Now we apply the value of x in (1)

x + (576/x) = 60

(x2 + 576) / x = 60

x2 + 576 = 60x

x2 - 60x + 576 = 0

(x - 12) (x - 48) = 0

x - 12 = 0

x = 12

If x = 12

y = 576 / 12

y = 48

x - 48 = 0

x = 48

If x = 48

y = 576 / 48

y = 12

So the required integers are 18 and The sum of two numbers is 60

48 + 18 = 60

60 = 60

The product is 576

48 (18) = 576

576 = 57648.

Two positive numbers differ by 4 and their product is 192. Find the numbers.

Let x and y be two positive numbers

It differs by 4

x - y = 4

x = 4 + y --- (1)

Their product is 192

xy = 192

y = 192/x --- (2)

By applying the value of y in (1), we get

x = 4 + (192/x)

x = (4x + 192)/x

x2 = 4x + 192

x2 - 4 x - 192 = 0

(x - 16) (x + 12) = 0

x - 16 = 0

x = 16

x + 12 = 0

x = -12

If x = 16

Then,

y = 192/16

y = 12

Since it is positive number we have to choose 16 for x.

User DotNetBeginner
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