Answer:
The value moment of inertia the disk:
I = 6.4 kg·m²
Step-by-step explanation:
Given:
Tk = 70 J
L = 30 kg·m² / s
_____________
I - ?
Rotational kinetic energy:
Tk = I·ω²/2
Angular velocity:
ω = √ (2·T / I)
Angular moment of a rotating body
L = I·ω = I·√ (2·T / I) = √ (2·T·I² / I ) = √ (2·T·I )
Raising to the second degree:
L² = 2·T·I
The value moment of inertia the disk:
I = L² / (2·T)
I = 30² / (2·70) ≈ 6.4 kg·m²
А) 6.4 кг·м²