Question

Sal's Sandwich Shop sells wraps and sandwiches as part of its lunch specials. The profit on every sandwich is $2, and the profit on every wrap is $3. Sal made a profit of $1,470 from lunch specials last month. The equation 2x + 3y = 1,470 represents Sal's profits last month, where x is the number of sandwich lunch specials sold and y is the number of wrap lunch specials sold.

Change the equation to slope-intercept form. Identify the slope and y-intercept of the equation. Be sure to show all your work.
Describe how you would graph this line using the slope-intercept method. Be sure to write using complete sentences.
Write the equation in function notation. Explain what the graph of the function represents. Be sure to use complete sentences.
Graph the function. On the graph, make sure to label the intercepts. You may graph your equation by hand on a piece of paper

Answer 1

Answer:(1) y-intercept exists 490 and the slope is -2/3x.

(2) First, I observe the point (0,490) and plot a point there. Then utilize our slope -2/3 to compute the direction and angle the line moves by measuring 2 down and 3 to the right.

(3) The equation of the function is

The diagram illustrates how many wraps could've been sold for each number of sandwich sales to maintain the identical earnings of $1,470.

(4) The graph of the equation is shown below.

(5) The profits exist the same (slope) but the y-intercept is more increased than the actual diagram.

(6) The equation is

Explanation:

(1)

slope-intercept form of a linear equation is where one side includes only "y".

⇒

⇒

Therefore,

.

Hence, the y-intercept exists at 490 and the slope is -2/3x.

(2)

I would graph this line using the slope-intercept method First, I observe the point (0,490) and plot a point there. Then utilize our slope -2/3 to compute the direction and angle the line moves by measuring 2 down and 3 to the right.

(3)

The equation of the function is. The diagram illustrates how many wraps could've been sold for each number of sandwich sales to maintain the identical earnings of $1,470.

(4)

The graph of the function is shown below,

(5)

Therefore,

The profits exist the same (slope) but the y-intercept is more increased than the actual diagram.

(6)

y intercept= 300

The equation will be,