Final answer:
To find the logarithm of log(b)(1/63), we can apply the property of logarithms that states the logarithm of the quotient of two numbers is equal to the difference of their logarithms.
Step-by-step explanation:
To find the logarithm of logb(1/63), we can apply the property of logarithms that states the logarithm of the quotient of two numbers is equal to the difference of their logarithms. So, we have:
logb(1/63) = logb(1) - logb(63)
Since logb(1) = 0, we just need to find logb(63). Since 63 can be expressed as the product of 7 and 9, we can use the property of logarithms that states the logarithm of a product is equal to the sum of the logarithms of the factors:
logb(63) = logb(7) + logb(9)
Substituting the given values, we have:
logb(1/63) = 0 - (1.946 + 2.197) = -4.143