Question

Suppose that there are two types of tickets to a show: advance and same-day. Advance tickets cost $25 and same-day tickets cost $15. For one performance, there were 55 tickets sold in all, and the total amount paid for them was $1025. How many tickets of each type were sold?

Answer 1

• advance: 20
• same-day: 35

Explanation:

You have tickets that sell for $25 and $15, and you sold 55 tickets for $1025. You want to know the number of each sold.

Setup

Let 'a' represent the number of advance tickets sold. Then 55-a is the number of same-day tickets sold. The total revenue is ...

25a +15(55 -a) = 1025

Solution

10a + 825 = 1025 . . . . . simplify

10a = 200 . . . . . . . . . . subtract 825

a = 20 . . . . . . . . . . . divide by 10; the number of advance tickets

55 -20 = 35 . . . . the number of same-day tickets

20 advance tickets and 35 same-day tickets were sold.