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A worker lifts a 10 kilogram block a vertical height of 2 meters. The work he does on the block is:

User LcSalazar
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2 Answers

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So yeah I think it’s this
A worker lifts a 10 kilogram block a vertical height of 2 meters. The work he does-example-1
User Nikhil Baby
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Answer:

Work = 196 Joules (1 kg*m^2/sec^2 is 1 Joule)

Step-by-step explanation:

Work, W, is defined as force. F, times displacement, d.

W = Force*displacement

In the worker's case, the force he/she is struggling against is Earth's gravity's acceleration, g, (9.8 m/sec^2) times the mass, m.

Force = mg

Force = (10kg)*(9.8 m/sec^2) = 98 kg*m/sec^2

Use this force in the work calculation.

W = Force*displacement

The displacement is 2 meters.

Work = (98 kg*m/sec^2)*(2 meters) = 196 kg*m^2/sec^2

1 kg*m^2/sec^2 is 1 Joule

Work = 196 Joules

User Wbharding
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