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What is the volume in liters of hydrogen gas that would be produced by the reaction of 55.0 g of Al with excess HCl at STP according to the following reaction? 2 Al (s) + 6 HCl (aq) → 2 AlCl₃ (aq) + 3
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What is the volume in liters of hydrogen gas that would be produced by the reaction of 55.0 g of Al with excess HCl at STP according to the following reaction?

2 Al (s) + 6 HCl (aq) → 2 AlCl₃ (aq) + 3 H₂ (g)

User Jason De Oliveira
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1 Answer

5 votes

Answer:

About 68.495 L hydrogen gas

Step-by-step explanation:

What is the volume in liters of hydrogen gas that would be produced by the reaction-example-1
User Ebraheem Alrabeea
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