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Y = 6x
y = x^2 - 7 + 12

Solve the system of equation

1 Answer

8 votes

Answer:

I'm not sure if there's a typo so I did both

When y = x^2 - 7 + 12: x=5 or x=1 , y = 6 or 30

When y = x^2 -7x + 12: x = 12 or x = 1, y = 72 or 6

Step-by-step explanation for y = x^2 -7 + 12:

Simplify

y=6x

y = x^2+5

Substitute y = 6x into the quadratic

6x = x^2+5

Make the quadratic equate to 0

6x = x^2+5

-6x -6x

0 = x^2 - 6x + 5

Factor

What multiplies to c and adds to b?

(x-5)(x-1) = 0

Solve for small equations

x-5 = 0 x-1 = 0

+5 +5 +1 +1

x=5 or x=1

Substitute to find y

y = 6 (5 or 1)

y = 6 or 30

Step-by-step explanation for y = x^2 -7x + 12:

Equate y to 6x

6x = x^2 - 7x + 12

Equate to 0

6x = x^2 - 7x + 12

-6x -6x

0 = x^2 - 13x + 12

Factor

What multiplies to c and adds to b?

(x - 12)(x - 1)

Solve for x

x-12 = 0 x-1 = 0

+12 +12 +1 +1

x = 12 or x = 1

Substitute for x to find y

y = 6(12 or 1)

y = 72 or 6

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