Question

SOMEONE HELP PLEASE

Answer 1

⇒The volume is given and the height is give. In the equation
`V=\pi r^(2) h`plug in the known value V which is equal to
`(160\pi )m^(3)` and h which is equal to 8m and solve for r which is the radius

⇒
`160\pi =\pi r^(2) *(8)\\(160\pi)/(\pi ) =(\pi r^(2) *(8))/(\pi ) \\160=8r^(2) \\8r^(2) -160=0\\8(r^(2) -20)=0\\(8(r^(2) -20))/(8) =(0)/(8) \\r^(2) -20=0\\(r+√(20) )(r-√(20) )=0\\r+√(20) =0\\or\\r-√(20) =0\\\\r=2√(5) \\or\\r= -2√(5)`

⇒Note radius is a distance therefore it cannot be negative meaning radius r is equal to
`√(20) =2√(5)`m

expressed in decimal is 4.5m