What is the sum of a geometric series of 12 terms that begins with 10 and has a common ratio of 2?

asked May 23, 2023 93.9k views

1 vote

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6 votes

Answer:

40950

Explanation:

$S_n=(a_1(1-r^n))/(1-r)\\\\S_(12)=(10(1-(2)^(12)))/(1-2)\\\\S_(12)=(10(1-4096))/(-1)\\\\S_(12)=(10(-4095))/(-1)\\\\S_(12)=10(4095)\\\\S_(12)=40950$

RobertW answered May 27, 2023

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