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A pot of soup, currently 74°C above room temperature, is left out to cool. If that temperature difference decreases by 5% per minute, then what will the difference be in 14 minutes? If necessary, round
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Mar 14, 2023
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A pot of soup, currently 74°C above room temperature, is left out to cool. If that temperature
difference decreases by 5% per minute, then what will the difference be in 14 minutes?
If necessary, round your answer to the nearest tenth.
°C
Mathematics
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Sergio Monteleone
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A decrease of 5% is a multiplier of 0.95 (since 100% = 1). Like with the other question, compound the rate so after 14 minutes the multiplier is 0.95^14. Multiply this by the starting temperature to give 74 x 0.95^14 = 36°C, so a difference of 74 - 36 = 38°C
Andre Dublin
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Mar 15, 2023
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Answer:36.1
Explanation:
ixl
Onpduo
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Mar 20, 2023
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