Question

A chemist burns isopropyl alcohol (C3H8O) according to the following equation: C3H8O + 3 O2 → 3 CO + 4 H2O If he burns 275 grams of C3H8O in excess oxygen, how many grams of water will be made?

Answer 1

329.8g of H2O are produced

Step-by-step explanation:

You have to do stoichiometry to convert grams of isopropyl alcohol to grams of water.

1. Convert grams of isopropyl alcohol to moles of isopropyl alcohol (use molar mass of isopropyl alcohol)
2. Convert this to moles of water using molar coefficients
3. Convert moles of water to grams (use molar mass of water)
   
   
   `(275g C3H8O)/(1) * (1 mol C3H8O)/(60.1g ) * (4 mol H2O)/(1 mol H2O) * (18.01g)/(1 mol H2O)`
   
   This gives you 329.8g of water