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If x²+kx+16/9 is a perfect square. Find the value of k​

User Leonheess
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1 Answer

5 votes

Answer:

For x² + kx + 16/9 to be a perfect square, k should be equal to 8/3

Explanation:

If x² + kx + 16/9 is a perfect square then it must satisfy the formula of (a + b)² i.e. equal to a² + 2ab + b².

So, first we will form a equal that looks similar to the formula:


\rm \implies {x}^(2) + kx + (4 * 4)/(3 * 3) \\ \\ \rm \implies {x}^(2) + kx + { \bigg( (4)/(3) } \bigg)^(2)

Now by comparing we get,


\rm \implies k \cancel{x} = 2 * \cancel{x}* (4)/(3) \\ \\ \rm \implies k = (8)/(3)

User Jurek
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