Question

To what temperature should an aluminum bar be heated in order to increase its length by 1% in relative to length at O°C? alpha is =2.4× 10⁵ 1°C​

Answer 1

Step-by-step explanation:

Given:

ΔL / L₀ = 0.01

t₀ = 0°C

α = 2.4·10⁻⁵ 1/°C

_______________

t - ?

L = L₀· (1 + α·Δt)

L = L₀ + L₀·α·Δt

ΔL = L₀·α·Δt

α·Δt = ΔL / L₀

Δt = (ΔL/L₀) / α

Δt = 0.01 / 2.4·10⁻⁵ ≈ 417°C

Δt = t - t₀

t = t₀ + Δt = 0 + 417 = 417°C