Question

A balloon filled with helium has a volume of 30.0 L at a pressure of 100 kPa and a temperature of 15.0°C. What will the volume of the balloon be if the temperature is decreased to -80.0°C and the pressure remains constant?

Answer 1

`V_2=20.1L`

Step-by-step explanation:

Hello there!

In this case, since this is a problem in which the pressure of the gas remains constant, we can use the Charles' law as a directly proportional relationship between temperature (in Kelvins) and volume given by:

`(V_2)/(T_2) =(V_1)/(T_1)`

Thus, solving for the final volume as the temperature is decreased to -80.00 °C, we obtain:

`V_2=(V_1T_2)/(T_1)`

`V_2=(30.0L*(-80+273)K)/((15+273)K) \\\\V_2=20.1L`

Best regards!