214k views
2 votes
O

-10
-10
O A. y=-2x
OB. y = 2x
O C. y--1x
OD. y=x
in
(1,-2)
(2,-4)
10
C
4

O -10 -10 O A. y=-2x OB. y = 2x O C. y--1x OD. y=x in (1,-2) (2,-4) 10 C 4-example-1
User Adamwong
by
7.8k points

2 Answers

4 votes

Answer: A

Explanation:

Using the given points, the slope is
(-4-(-2))/(2-1)=-2. So, since the line passes through the origin, the equation is
y=-2x.

User Hubert Schumacher
by
8.2k points
4 votes

Answer: A. y = -2x

Explanation:

First, we will use the slope formula to find the slope of our line.


\displaystyle (y_(2) -y_(1) )/(x_(2) -x_(1) ) =(-4--2)/(2-1) =(-2)/(1) =-2

Next, our y-intercept is given. This is the point at which the line intercepts the y-axis. The y-intercept is 0 since the line intercepts at (0, 0).

Now, we can write our slope-intercept form equation.

y = mx + b

y = -2x + 0

y = -2x

User Jane Doh
by
7.4k points

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