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using activities correctly, calculate the ph of a solution containing 0.010 m naoh plus 0.0120 m lino3. what would the ph be if you neglected activities?

User Arunan
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Final answer:

To calculate the pH of the given solution, we use the concentration of NaOH, which is 0.010 M, to find the concentration of H3O+ ions. The concentration of H3O+ ions is found to be 1.0 x 10^-12 M, and the pH of the solution is calculated to be 12.00.

Step-by-step explanation:

To calculate the pH of a solution containing 0.010 M NaOH and 0.0120 M LiNO3, we first need to determine the concentration of H3O+ ions. Since NaOH is a strong base, it completely dissociates in water to give OH- ions. The concentration of OH- ions is equal to the concentration of NaOH, which is 0.010 M.

Using the equation [H3O+] = 10^-14 / [OH-], the concentration of H3O+ ions can be calculated as follows: [H3O+] = 10^-14 / 0.010 = 1.0 x 10^-12 M.

Finally, the pH can be determined using the equation pH = -log [H3O+]. Substituting the value we calculated earlier, we have pH = -log (1.0 x 10^-12) = 12.00.

User Mike Ante
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