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Telisa · Answer 1 · 2023-04-09T13:57:37+0000

Answer: Mass of LiOH = (1.54 × 10⁻³ mol) × (23.9 g/mol) = 0.0368 g ==== OR: [ (1 × 10⁻¹⁴)/10⁻¹¹·⁷¹ mol OH⁻ ions / 1000 mL solution] × (300 mL solution) × (1 mol LiOH / 1 mol OH⁻ ions) × (23.9 g LiOH / 1 mol LiOH)

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