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Calculate the number of moles in 75.0 g of dinitrogen trioxide (n2o3). 0.987 mol 1.24 mol 1.63 mol 1.70 mol
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Mar 25, 2023
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Calculate the number of moles in 75.0 g of dinitrogen trioxide (n2o3). 0.987 mol 1.24 mol 1.63 mol 1.70 mol
Chemistry
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Aphrodite
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Answer:
A .987
Step-by-step explanation:
Guy above me is correct
Random Human
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Mar 27, 2023
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Random Human
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Numbers of Moles = mass/molar mass
=75.0/76.0 = 0.98
Keith Rome
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Apr 1, 2023
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