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A ball is thrown vertically down from the edge of a cliff with a speed of 4 m/s, how high is the cliff, if it took 12s for the ball to reach the ground?
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A ball is thrown vertically down from the edge of a cliff with a speed of 4 m/s, how high is the cliff, if it took 12s for the ball to reach the ground?

User Wiener
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1 Answer

4 votes

Answer:

754 m

Step-by-step explanation:

d = vot + 1/2 at^2

d = height = 4 (12) + 1/2 (9.81)(12^2) = 754 m

User Abhinav Sarkar
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3.1k points
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