Answer:
11 and 44
Explanation:
let the 2 numbers be x and y ( with x the larger number ), then
x + y = 55 → (1)
3y + 11 = x → ()
substitute x = 3y + 11 into (1)
3y + 11 + y = 55
4y + 11 = 55 ( subtract 11 from both sides )
4y = 44 ( divide both sides by 4 )
y = 11
substitute y = 11 into (1)
x + 11 = 55 ( subtract 11 from both sides )
y = 44
smaller number is 11 and larger number is 44