Register
The sum of 4 consecutive integers is 46. What is the least of the 4 integers?
7.2k views
2 votes
The sum of 4 consecutive integers is 46. What is the least of the 4 integers?

User Simon Chiu
by
3.8k points

1 Answer

4 votes
46 divided by 4 is 11.5, meaning 2 integers will be higher, and 2 will be lower. Therefore, the integers are 10, 11, 12, and 13 (10+11+12+13=46). Therefore, the smallest integer is 10.
User Cappittall
by
3.4k points
Ask a Question
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

3.6m questions

4.6m answers

Other Questions

A study was completed in Florida. In southern Florida, the study involved 3,000 patients; 54% of them experienced flulike symptoms during the same month. The study had a margin of error of 1.8%. What does
Solve for x in the equation 3 x squared minus 18 x + 5 = 47. (I need this to be an answer like X=3+\_ square root 23)
Can someone help me plz I have to Turn 27/9 in simplest
The sanchez family goes out for dinner, and the price of the meals is $60. The sales tax on the Meals is 7 percent, and they also want to leave a 15 percent tip. What is the total cost of the meal? Analyze
Simplify: 10 ÷ [(5 + 2) − 5]
Link Copied!