Question

Help please with these questions

Answer 1

5.⇒I will use substitution method to solve this system of equations.

a=8+b......(1st equation)

a=20-b(2nd equation)

`eq1=eq2\\8+b=20-b\\b+b=20-8\\2b=12\\(2b)/(2) =(12)/(2) \\b=6`

`a=20-b\\a=20-(6)\\a=14`

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y=2x....(1st equation)

6y+2x=0(2nd equation)

Plug in the first equation in the second equation.

Hint: in the place of y in the second equation plug in 2x

`6(2x)+2x=0\\8x=0\\(8x)/(8) =(0)/(8) \\x=0`

`y=2x\\y=2(0)\\y=0`

Goodluck

Answer 2

1. A is 14 B is 6. 14+6 is 20 and 14-6 is 8.
2. Both X and Y are 0. 0 - 0 is 0 and 0+0 is 0.