Question

Can someone help?

Solve the following equation for all values of x. Be sure to check for extraneous roots.

Answer 1

`x=2`

Explanation:

First, let's multiply both sides by
`√(x+11)`. If we do this, we would have:

`x-1=(1)/(√(x+11))\cdot√(x+11)`

The
`√(x+11)` would cancel out and we would be left with:

`x-1=1`

If we add 1 on both sides, we would get:

`x=2`

Hope this helps!!!