Question

6. Angle B= 110°, AC = 14 ft, BC = 7 ft, find Angle A

Answer 1

∠ A ≈ 28°

Explanation:

using the Sine rule in Δ ABC

`(BC)/(sinA)` =
`(AC)/(sin110)` , that is

`(7)/(sinA)` =
`(14)/(sin110)` ( cross- multiply )

14 × sinA = 7 × sin110° ( divide both sides by 14 )

sinA =
`(7sin110)/(14)` , then

∠ A =
`sin^(-1)` (
`(7sin110)/(14)` ) ≈ 28° ( to the nearest degree )